7(4+4r)=5(5r+2)

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Solution for 7(4+4r)=5(5r+2) equation: 



7(4+4r)=5(5r+2)

We move all terms to the left:

7(4+4r)-(5(5r+2))=0

We add all the numbers together, and all the variables

7(4r+4)-(5(5r+2))=0

We multiply parentheses

28r-(5(5r+2))+28=0



We calculate terms in parentheses: -(5(5r+2)), so:

5(5r+2)

We multiply parentheses

25r+10

Back to the equation:

-(25r+10)



We get rid of parentheses

28r-25r-10+28=0

We add all the numbers together, and all the variables

3r+18=0

We move all terms containing r to the left, all other terms to the right

3r=-18

r=-18/3

r=-6

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