7(4+5)=6(x-2)+15

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Solution for 7(4+5)=6(x-2)+15 equation: 



7(4+5)=6(x-2)+15

We move all terms to the left:

7(4+5)-(6(x-2)+15)=0

We add all the numbers together, and all the variables

-(6(x-2)+15)+79=0



We calculate terms in parentheses: -(6(x-2)+15), so:

6(x-2)+15

We multiply parentheses

6x-12+15

We add all the numbers together, and all the variables

6x+3

Back to the equation:

-(6x+3)



We get rid of parentheses

-6x-3+79=0

We add all the numbers together, and all the variables

-6x+76=0

We move all terms containing x to the left, all other terms to the right

-6x=-76

x=-76/-6

x=12+2/3

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