7(4+9)=3(9+u)

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Solution for 7(4+9)=3(9+u) equation: 



7(4+9)=3(9+u)

We move all terms to the left:

7(4+9)-(3(9+u))=0

We add all the numbers together, and all the variables

-(3(u+9))+713=0



We calculate terms in parentheses: -(3(u+9)), so:

3(u+9)

We multiply parentheses

3u+27

Back to the equation:

-(3u+27)



We get rid of parentheses

-3u-27+713=0

We add all the numbers together, and all the variables

-3u+686=0

We move all terms containing u to the left, all other terms to the right

-3u=-686

u=-686/-3

u=228+2/3

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