7(4+a)=3(a-4)

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Solution for 7(4+a)=3(a-4) equation:


Simplifying
7(4 + a) = 3(a + -4)
(4 * 7 + a * 7) = 3(a + -4)
(28 + 7a) = 3(a + -4)

Reorder the terms:
28 + 7a = 3(-4 + a)
28 + 7a = (-4 * 3 + a * 3)
28 + 7a = (-12 + 3a)

Solving
28 + 7a = -12 + 3a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-3a' to each side of the equation.
28 + 7a + -3a = -12 + 3a + -3a

Combine like terms: 7a + -3a = 4a
28 + 4a = -12 + 3a + -3a

Combine like terms: 3a + -3a = 0
28 + 4a = -12 + 0
28 + 4a = -12

Add '-28' to each side of the equation.
28 + -28 + 4a = -12 + -28

Combine like terms: 28 + -28 = 0
0 + 4a = -12 + -28
4a = -12 + -28

Combine like terms: -12 + -28 = -40
4a = -40

Divide each side by '4'.
a = -10

Simplifying
a = -10

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