7(4+c)=6(c-2)

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Solution for 7(4+c)=6(c-2) equation:


Simplifying
7(4 + c) = 6(c + -2)
(4 * 7 + c * 7) = 6(c + -2)
(28 + 7c) = 6(c + -2)

Reorder the terms:
28 + 7c = 6(-2 + c)
28 + 7c = (-2 * 6 + c * 6)
28 + 7c = (-12 + 6c)

Solving
28 + 7c = -12 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
28 + 7c + -6c = -12 + 6c + -6c

Combine like terms: 7c + -6c = 1c
28 + 1c = -12 + 6c + -6c

Combine like terms: 6c + -6c = 0
28 + 1c = -12 + 0
28 + 1c = -12

Add '-28' to each side of the equation.
28 + -28 + 1c = -12 + -28

Combine like terms: 28 + -28 = 0
0 + 1c = -12 + -28
1c = -12 + -28

Combine like terms: -12 + -28 = -40
1c = -40

Divide each side by '1'.
c = -40

Simplifying
c = -40

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