7(4+f)=7(4+f)

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Solution for 7(4+f)=7(4+f) equation: 



7(4+f)=7(4+f)

We move all terms to the left:

7(4+f)-(7(4+f))=0

We add all the numbers together, and all the variables

7(f+4)-(7(f+4))=0

We multiply parentheses

7f-(7(f+4))+28=0



We calculate terms in parentheses: -(7(f+4)), so:

7(f+4)

We multiply parentheses

7f+28

Back to the equation:

-(7f+28)



We get rid of parentheses

7f-7f-28+28=0

We add all the numbers together, and all the variables

=0

f=0/1

f=0

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