7(4+m)=31+4m

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Solution for 7(4+m)=31+4m equation: 



7(4+m)=31+4m

We move all terms to the left:

7(4+m)-(31+4m)=0

We add all the numbers together, and all the variables

7(m+4)-(4m+31)=0

We multiply parentheses

7m-(4m+31)+28=0

We get rid of parentheses

7m-4m-31+28=0

We add all the numbers together, and all the variables

3m-3=0

We move all terms containing m to the left, all other terms to the right

3m=3

m=3/3

m=1

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