7(4+n)=35

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Solution for 7(4+n)=35 equation: 



7(4+n)=35

We move all terms to the left:

7(4+n)-(35)=0

We add all the numbers together, and all the variables

7(n+4)-35=0

We multiply parentheses

7n+28-35=0

We add all the numbers together, and all the variables

7n-7=0

We move all terms containing n to the left, all other terms to the right

7n=7

n=7/7

n=1

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