7(4-2k)=12(k-2)

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Solution for 7(4-2k)=12(k-2) equation: 



7(4-2k)=12(k-2)

We move all terms to the left:

7(4-2k)-(12(k-2))=0

We add all the numbers together, and all the variables

7(-2k+4)-(12(k-2))=0

We multiply parentheses

-14k-(12(k-2))+28=0



We calculate terms in parentheses: -(12(k-2)), so:

12(k-2)

We multiply parentheses

12k-24

Back to the equation:

-(12k-24)



We get rid of parentheses

-14k-12k+24+28=0

We add all the numbers together, and all the variables

-26k+52=0

We move all terms containing k to the left, all other terms to the right

-26k=-52

k=-52/-26

k=+2

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