7(4-3x)+3(2+5x)=32

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Solution for 7(4-3x)+3(2+5x)=32 equation:



7(4-3x)+3(2+5x)=32
We move all terms to the left:
7(4-3x)+3(2+5x)-(32)=0
We add all the numbers together, and all the variables
7(-3x+4)+3(5x+2)-32=0
We multiply parentheses
-21x+15x+28+6-32=0
We add all the numbers together, and all the variables
-6x+2=0
We move all terms containing x to the left, all other terms to the right
-6x=-2
x=-2/-6
x=1/3

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