7(4-3x)=-8(2x-1)

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Solution for 7(4-3x)=-8(2x-1) equation:



7(4-3x)=-8(2x-1)
We move all terms to the left:
7(4-3x)-(-8(2x-1))=0
We add all the numbers together, and all the variables
7(-3x+4)-(-8(2x-1))=0
We multiply parentheses
-21x-(-8(2x-1))+28=0
We calculate terms in parentheses: -(-8(2x-1)), so:
-8(2x-1)
We multiply parentheses
-16x+8
Back to the equation:
-(-16x+8)
We get rid of parentheses
-21x+16x-8+28=0
We add all the numbers together, and all the variables
-5x+20=0
We move all terms containing x to the left, all other terms to the right
-5x=-20
x=-20/-5
x=+4

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