7(4-3x)=2(8x-9)+6=

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Solution for 7(4-3x)=2(8x-9)+6= equation: 



7(4-3x)=2(8x-9)+6=

We move all terms to the left:

7(4-3x)-(2(8x-9)+6)=0

We add all the numbers together, and all the variables

7(-3x+4)-(2(8x-9)+6)=0

We multiply parentheses

-21x-(2(8x-9)+6)+28=0



We calculate terms in parentheses: -(2(8x-9)+6), so:

2(8x-9)+6

We multiply parentheses

16x-18+6

We add all the numbers together, and all the variables

16x-12

Back to the equation:

-(16x-12)



We get rid of parentheses

-21x-16x+12+28=0

We add all the numbers together, and all the variables

-37x+40=0

We move all terms containing x to the left, all other terms to the right

-37x=-40

x=-40/-37

x=1+3/37

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