7(4-3x+12(x-5)x8)=-7(x+5)+2x

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Solution for 7(4-3x+12(x-5)x8)=-7(x+5)+2x equation: 



7(4-3x+12(x-5)x8)=-7(x+5)+2x

We move all terms to the left:

7(4-3x+12(x-5)x8)-(-7(x+5)+2x)=0



We calculate terms in parentheses: -(-7(x+5)+2x), so:

-7(x+5)+2x

We add all the numbers together, and all the variables

2x-7(x+5)

We multiply parentheses

2x-7x-35

We add all the numbers together, and all the variables

-5x-35

Back to the equation:

-(-5x-35)



We get rid of parentheses

7(4-3x+12(x-5)x8)+5x+35=0

We add all the numbers together, and all the variables

5x+7(4-3x+12(x-5)x8)+35=0

We move all terms containing x to the left, all other terms to the right

5x+7(4-3x+12(x-5)x8)=-35

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