7(4-a)=3(a-12)

Solution for 7(4-a)=3(a-12) equation:

7(4-a)=3(a-12)

We move all terms to the left:

7(4-a)-(3(a-12))=0

We add all the numbers together, and all the variables

7(-1a+4)-(3(a-12))=0

We multiply parentheses

-7a-(3(a-12))+28=0


We calculate terms in parentheses: -(3(a-12)), so:

3(a-12)

We multiply parentheses

3a-36

Back to the equation:

-(3a-36)


We get rid of parentheses

-7a-3a+36+28=0

We add all the numbers together, and all the variables

-10a+64=0

We move all terms containing a to the left, all other terms to the right

-10a=-64

a=-64/-10

a=6+2/5