7(4-a)=3(a-47)

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Solution for 7(4-a)=3(a-47) equation: 



7(4-a)=3(a-47)

We move all terms to the left:

7(4-a)-(3(a-47))=0

We add all the numbers together, and all the variables

7(-1a+4)-(3(a-47))=0

We multiply parentheses

-7a-(3(a-47))+28=0



We calculate terms in parentheses: -(3(a-47)), so:

3(a-47)

We multiply parentheses

3a-141

Back to the equation:

-(3a-141)



We get rid of parentheses

-7a-3a+141+28=0

We add all the numbers together, and all the variables

-10a+169=0

We move all terms containing a to the left, all other terms to the right

-10a=-169

a=-169/-10

a=16+9/10

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