7(4-p)=3(p-4)

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Solution for 7(4-p)=3(p-4) equation: 



7(4-p)=3(p-4)

We move all terms to the left:

7(4-p)-(3(p-4))=0

We add all the numbers together, and all the variables

7(-1p+4)-(3(p-4))=0

We multiply parentheses

-7p-(3(p-4))+28=0



We calculate terms in parentheses: -(3(p-4)), so:

3(p-4)

We multiply parentheses

3p-12

Back to the equation:

-(3p-12)



We get rid of parentheses

-7p-3p+12+28=0

We add all the numbers together, and all the variables

-10p+40=0

We move all terms containing p to the left, all other terms to the right

-10p=-40

p=-40/-10

p=+4

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