7(4-x)=5(x-4)+5x

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Solution for 7(4-x)=5(x-4)+5x equation: 



7(4-x)=5(x-4)+5x

We move all terms to the left:

7(4-x)-(5(x-4)+5x)=0

We add all the numbers together, and all the variables

7(-1x+4)-(5(x-4)+5x)=0

We multiply parentheses

-7x-(5(x-4)+5x)+28=0



We calculate terms in parentheses: -(5(x-4)+5x), so:

5(x-4)+5x

We add all the numbers together, and all the variables

5x+5(x-4)

We multiply parentheses

5x+5x-20

We add all the numbers together, and all the variables

10x-20

Back to the equation:

-(10x-20)



We get rid of parentheses

-7x-10x+20+28=0

We add all the numbers together, and all the variables

-17x+48=0

We move all terms containing x to the left, all other terms to the right

-17x=-48

x=-48/-17

x=2+14/17

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