7(4-y)-18+6=-7y+16

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Solution for 7(4-y)-18+6=-7y+16 equation: 



7(4-y)-18+6=-7y+16

We move all terms to the left:

7(4-y)-18+6-(-7y+16)=0

We add all the numbers together, and all the variables

7(-1y+4)-(-7y+16)-18+6=0

We add all the numbers together, and all the variables

7(-1y+4)-(-7y+16)-12=0

We multiply parentheses

-7y-(-7y+16)+28-12=0

We get rid of parentheses

-7y+7y-16+28-12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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