7(4b+1)=63

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Solution for 7(4b+1)=63 equation: 



7(4b+1)=63

We move all terms to the left:

7(4b+1)-(63)=0

We multiply parentheses

28b+7-63=0

We add all the numbers together, and all the variables

28b-56=0

We move all terms containing b to the left, all other terms to the right

28b=56

b=56/28

b=2

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