7(4f-3)=5(2f+3)

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Solution for 7(4f-3)=5(2f+3) equation: 



7(4f-3)=5(2f+3)

We move all terms to the left:

7(4f-3)-(5(2f+3))=0

We multiply parentheses

28f-(5(2f+3))-21=0



We calculate terms in parentheses: -(5(2f+3)), so:

5(2f+3)

We multiply parentheses

10f+15

Back to the equation:

-(10f+15)



We get rid of parentheses

28f-10f-15-21=0

We add all the numbers together, and all the variables

18f-36=0

We move all terms containing f to the left, all other terms to the right

18f=36

f=36/18

f=2

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