7(4k-15)=-6(4+2k)

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Solution for 7(4k-15)=-6(4+2k) equation: 



7(4k-15)=-6(4+2k)

We move all terms to the left:

7(4k-15)-(-6(4+2k))=0

We add all the numbers together, and all the variables

7(4k-15)-(-6(2k+4))=0

We multiply parentheses

28k-(-6(2k+4))-105=0



We calculate terms in parentheses: -(-6(2k+4)), so:

-6(2k+4)

We multiply parentheses

-12k-24

Back to the equation:

-(-12k-24)



We get rid of parentheses

28k+12k+24-105=0

We add all the numbers together, and all the variables

40k-81=0

We move all terms containing k to the left, all other terms to the right

40k=81

k=81/40

k=2+1/40

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