7(4n+4)=2(7n-3)=15n

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Solution for 7(4n+4)=2(7n-3)=15n equation: 



7(4n+4)=2(7n-3)=15n

We move all terms to the left:

7(4n+4)-(2(7n-3))=0

We multiply parentheses

28n-(2(7n-3))+28=0



We calculate terms in parentheses: -(2(7n-3)), so:

2(7n-3)

We multiply parentheses

14n-6

Back to the equation:

-(14n-6)



We get rid of parentheses

28n-14n+6+28=0

We add all the numbers together, and all the variables

14n+34=0

We move all terms containing n to the left, all other terms to the right

14n=-34

n=-34/14

n=-2+3/7

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