7(4n+4)=2(7n-3)=15n

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Solution for 7(4n+4)=2(7n-3)=15n equation:



7(4n+4)=2(7n-3)=15n
We move all terms to the left:
7(4n+4)-(2(7n-3))=0
We multiply parentheses
28n-(2(7n-3))+28=0
We calculate terms in parentheses: -(2(7n-3)), so:
2(7n-3)
We multiply parentheses
14n-6
Back to the equation:
-(14n-6)
We get rid of parentheses
28n-14n+6+28=0
We add all the numbers together, and all the variables
14n+34=0
We move all terms containing n to the left, all other terms to the right
14n=-34
n=-34/14
n=-2+3/7

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