7(4n-3)-(11n-12)=3(7n+11)

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Solution for 7(4n-3)-(11n-12)=3(7n+11) equation: 



7(4n-3)-(11n-12)=3(7n+11)

We move all terms to the left:

7(4n-3)-(11n-12)-(3(7n+11))=0

We multiply parentheses

28n-(11n-12)-(3(7n+11))-21=0

We get rid of parentheses

28n-11n-(3(7n+11))+12-21=0



We calculate terms in parentheses: -(3(7n+11)), so:

3(7n+11)

We multiply parentheses

21n+33

Back to the equation:

-(21n+33)



We add all the numbers together, and all the variables

17n-(21n+33)-9=0

We get rid of parentheses

17n-21n-33-9=0

We add all the numbers together, and all the variables

-4n-42=0

We move all terms containing n to the left, all other terms to the right

-4n=42

n=42/-4

n=-10+1/2

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