7(4t+1)-10=t-(t+2)

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Solution for 7(4t+1)-10=t-(t+2) equation:


Simplifying
7(4t + 1) + -10 = t + -1(t + 2)

Reorder the terms:
7(1 + 4t) + -10 = t + -1(t + 2)
(1 * 7 + 4t * 7) + -10 = t + -1(t + 2)
(7 + 28t) + -10 = t + -1(t + 2)

Reorder the terms:
7 + -10 + 28t = t + -1(t + 2)

Combine like terms: 7 + -10 = -3
-3 + 28t = t + -1(t + 2)

Reorder the terms:
-3 + 28t = t + -1(2 + t)
-3 + 28t = t + (2 * -1 + t * -1)
-3 + 28t = t + (-2 + -1t)

Reorder the terms:
-3 + 28t = -2 + t + -1t

Combine like terms: t + -1t = 0
-3 + 28t = -2 + 0
-3 + 28t = -2

Solving
-3 + 28t = -2

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 28t = -2 + 3

Combine like terms: -3 + 3 = 0
0 + 28t = -2 + 3
28t = -2 + 3

Combine like terms: -2 + 3 = 1
28t = 1

Divide each side by '28'.
t = 0.03571428571

Simplifying
t = 0.03571428571

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