7(4t+1)-12=t-(t+4)

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Solution for 7(4t+1)-12=t-(t+4) equation: 



7(4t+1)-12=t-(t+4)

We move all terms to the left:

7(4t+1)-12-(t-(t+4))=0

We multiply parentheses

28t-(t-(t+4))+7-12=0



We calculate terms in parentheses: -(t-(t+4)), so:

t-(t+4)

We get rid of parentheses

t-t-4

We add all the numbers together, and all the variables

-4

Back to the equation:

-(-4)



We add all the numbers together, and all the variables

28t-1=0

We move all terms containing t to the left, all other terms to the right

28t=1

t=1/28

t=1/28

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