7(4v-5)=33-6v

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Solution for 7(4v-5)=33-6v equation: 



7(4v-5)=33-6v

We move all terms to the left:

7(4v-5)-(33-6v)=0

We add all the numbers together, and all the variables

7(4v-5)-(-6v+33)=0

We multiply parentheses

28v-(-6v+33)-35=0

We get rid of parentheses

28v+6v-33-35=0

We add all the numbers together, and all the variables

34v-68=0

We move all terms containing v to the left, all other terms to the right

34v=68

v=68/34

v=2

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