If it's not what You are looking for type in the equation solver your own equation and let us solve it.
7(4w+5)w=9
We move all terms to the left:
7(4w+5)w-(9)=0
We multiply parentheses
28w^2+35w-9=0
a = 28; b = 35; c = -9;
Δ = b2-4ac
Δ = 352-4·28·(-9)
Δ = 2233
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{2233}}{2*28}=\frac{-35-\sqrt{2233}}{56} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{2233}}{2*28}=\frac{-35+\sqrt{2233}}{56} $
| 4(-1+x)=0 | | .5(6x+18)+.25(4x-12)=2(2x-10) | | x+(x*12/100)=8999 | | 2n+83.76(4n-5)=573+5.3n | | 2(-4x+4)=-13 | | 82=-5v+7 | | 2x+5÷3x+4=3 | | 8+4(-6x-3)=-8 | | x+(x*12=8999 | | 4y=17=85 | | -4+4x=-6+6x | | 3+x/6x=1/2x+4/3 | | 6/7x=60/7 | | -5(8x-3)+4x=3 | | x+14=160 | | -6(4x=1)=7-11x | | 4r+7=-1 | | 5(1+n)=45 | | 1+j=2(2j+6) | | 6(y=2)-4=-10 | | z-3+7=12 | | (7x-4)+87=65 | | -15/4-7=x | | -5z+7=37 | | 1/3(x-2)=1/4(x+1) | | 1/2(-8/5x+4)=6 | | c-5.2=3.1 | | 1988=28(p+30) | | 3y-5=(4y+2)/2 | | 5(2k+3)-3k=4k+21 | | (5/6)x+7=x | | 6(x+7)=-6 |