7(4x+4)=2(7x-5)+15x

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Solution for 7(4x+4)=2(7x-5)+15x equation: 



7(4x+4)=2(7x-5)+15x

We move all terms to the left:

7(4x+4)-(2(7x-5)+15x)=0

We multiply parentheses

28x-(2(7x-5)+15x)+28=0



We calculate terms in parentheses: -(2(7x-5)+15x), so:

2(7x-5)+15x

We add all the numbers together, and all the variables

15x+2(7x-5)

We multiply parentheses

15x+14x-10

We add all the numbers together, and all the variables

29x-10

Back to the equation:

-(29x-10)



We get rid of parentheses

28x-29x+10+28=0

We add all the numbers together, and all the variables

-1x+38=0

We move all terms containing x to the left, all other terms to the right

-x=-38

x=-38/-1

x=+38

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