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7(4x+5)=(3x-1)
We move all terms to the left:
7(4x+5)-((3x-1))=0
We multiply parentheses
28x-((3x-1))+35=0
We calculate terms in parentheses: -((3x-1)), so:We get rid of parentheses
(3x-1)
We get rid of parentheses
3x-1
Back to the equation:
-(3x-1)
28x-3x+1+35=0
We add all the numbers together, and all the variables
25x+36=0
We move all terms containing x to the left, all other terms to the right
25x=-36
x=-36/25
x=-1+11/25
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