7(4x+5)=3(6x+7)+148

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Solution for 7(4x+5)=3(6x+7)+148 equation: 



7(4x+5)=3(6x+7)+148

We move all terms to the left:

7(4x+5)-(3(6x+7)+148)=0

We multiply parentheses

28x-(3(6x+7)+148)+35=0



We calculate terms in parentheses: -(3(6x+7)+148), so:

3(6x+7)+148

We multiply parentheses

18x+21+148

We add all the numbers together, and all the variables

18x+169

Back to the equation:

-(18x+169)



We get rid of parentheses

28x-18x-169+35=0

We add all the numbers together, and all the variables

10x-134=0

We move all terms containing x to the left, all other terms to the right

10x=134

x=134/10

x=13+2/5

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