7(4x+5)=6(x-4)-14

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Solution for 7(4x+5)=6(x-4)-14 equation:



7(4x+5)=6(x-4)-14
We move all terms to the left:
7(4x+5)-(6(x-4)-14)=0
We multiply parentheses
28x-(6(x-4)-14)+35=0
We calculate terms in parentheses: -(6(x-4)-14), so:
6(x-4)-14
We multiply parentheses
6x-24-14
We add all the numbers together, and all the variables
6x-38
Back to the equation:
-(6x-38)
We get rid of parentheses
28x-6x+38+35=0
We add all the numbers together, and all the variables
22x+73=0
We move all terms containing x to the left, all other terms to the right
22x=-73
x=-73/22
x=-3+7/22

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