7(4x-1/3)=5(6x+2)-1/3

Solution for 7(4x-1/3)=5(6x+2)-1/3 equation:

7(4x-1/3)=5(6x+2)-1/3

We move all terms to the left:

7(4x-1/3)-(5(6x+2)-1/3)=0

We add all the numbers together, and all the variables

7(+4x-1/3)-(5(6x+2)-1/3)=0

We multiply parentheses

28x-(5(6x+2)-1/3)-1/3*7=0

We calculate fractions


28x+(-(5(6x+2)-1*3*7)/()+()/()=0


We calculate terms in parentheses: +(-(5(6x+2)-1*3*7)/()+()/(), so:

-(5(6x+2)-1*3*7)/()+()/(

We add all the numbers together, and all the variables

-(5(6x+2)-1*3*7)/()+1

We multiply all the terms by the denominator


-(5(6x+2)-1*3*7)+1*()


We calculate terms in parentheses: -(5(6x+2)-1*3*7), so:

5(6x+2)-1*3*7

We add all the numbers together, and all the variables

5(6x+2)-21

We multiply parentheses

30x+10-21

We add all the numbers together, and all the variables

30x-11

Back to the equation:

-(30x-11)


We add all the numbers together, and all the variables

-(30x-11)

We get rid of parentheses

-30x+11

Back to the equation:

+(-30x+11)


We get rid of parentheses

28x-30x+11=0

We add all the numbers together, and all the variables

-2x+11=0

We move all terms containing x to the left, all other terms to the right

-2x=-11

x=-11/-2

x=5+1/2