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7(4x-3)+2(6x+8)=6(5x-4)-3(2x-6)+1
We move all terms to the left:
7(4x-3)+2(6x+8)-(6(5x-4)-3(2x-6)+1)=0
We multiply parentheses
28x+12x-(6(5x-4)-3(2x-6)+1)-21+16=0
We calculate terms in parentheses: -(6(5x-4)-3(2x-6)+1), so:We add all the numbers together, and all the variables
6(5x-4)-3(2x-6)+1
We multiply parentheses
30x-6x-24+18+1
We add all the numbers together, and all the variables
24x-5
Back to the equation:
-(24x-5)
40x-(24x-5)-5=0
We get rid of parentheses
40x-24x+5-5=0
We add all the numbers together, and all the variables
16x=0
x=0/16
x=0
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