7(4x-3)-4(3x+8)+25=3(4x+9)-43

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Solution for 7(4x-3)-4(3x+8)+25=3(4x+9)-43 equation:



7(4x-3)-4(3x+8)+25=3(4x+9)-43
We move all terms to the left:
7(4x-3)-4(3x+8)+25-(3(4x+9)-43)=0
We multiply parentheses
28x-12x-(3(4x+9)-43)-21-32+25=0
We calculate terms in parentheses: -(3(4x+9)-43), so:
3(4x+9)-43
We multiply parentheses
12x+27-43
We add all the numbers together, and all the variables
12x-16
Back to the equation:
-(12x-16)
We add all the numbers together, and all the variables
16x-(12x-16)-28=0
We get rid of parentheses
16x-12x+16-28=0
We add all the numbers together, and all the variables
4x-12=0
We move all terms containing x to the left, all other terms to the right
4x=12
x=12/4
x=3

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