7(4x-3)-4(3x+8)+25=3(4x+9)-43

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Solution for 7(4x-3)-4(3x+8)+25=3(4x+9)-43 equation: 



7(4x-3)-4(3x+8)+25=3(4x+9)-43

We move all terms to the left:

7(4x-3)-4(3x+8)+25-(3(4x+9)-43)=0

We multiply parentheses

28x-12x-(3(4x+9)-43)-21-32+25=0



We calculate terms in parentheses: -(3(4x+9)-43), so:

3(4x+9)-43

We multiply parentheses

12x+27-43

We add all the numbers together, and all the variables

12x-16

Back to the equation:

-(12x-16)



We add all the numbers together, and all the variables

16x-(12x-16)-28=0

We get rid of parentheses

16x-12x+16-28=0

We add all the numbers together, and all the variables

4x-12=0

We move all terms containing x to the left, all other terms to the right

4x=12

x=12/4

x=3

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