7(4x-3)=5+28x-26

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Solution for 7(4x-3)=5+28x-26 equation: 



7(4x-3)=5+28x-26

We move all terms to the left:

7(4x-3)-(5+28x-26)=0

We add all the numbers together, and all the variables

7(4x-3)-(28x-21)=0

We multiply parentheses

28x-(28x-21)-21=0

We get rid of parentheses

28x-28x+21-21=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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