7(4x-4)+3(17-4x)-5(3x+2)=-8

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Solution for 7(4x-4)+3(17-4x)-5(3x+2)=-8 equation: 



7(4x-4)+3(17-4x)-5(3x+2)=-8

We move all terms to the left:

7(4x-4)+3(17-4x)-5(3x+2)-(-8)=0

We add all the numbers together, and all the variables

7(4x-4)+3(-4x+17)-5(3x+2)-(-8)=0

We add all the numbers together, and all the variables

7(4x-4)+3(-4x+17)-5(3x+2)+8=0

We multiply parentheses

28x-12x-15x-28+51-10+8=0

We add all the numbers together, and all the variables

x+21=0

We move all terms containing x to the left, all other terms to the right

x=-21

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