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7(4x-4)-3(5x-12)=3(4x+2)-1
We move all terms to the left:
7(4x-4)-3(5x-12)-(3(4x+2)-1)=0
We multiply parentheses
28x-15x-(3(4x+2)-1)-28+36=0
We calculate terms in parentheses: -(3(4x+2)-1), so:We add all the numbers together, and all the variables
3(4x+2)-1
We multiply parentheses
12x+6-1
We add all the numbers together, and all the variables
12x+5
Back to the equation:
-(12x+5)
13x-(12x+5)+8=0
We get rid of parentheses
13x-12x-5+8=0
We add all the numbers together, and all the variables
x+3=0
We move all terms containing x to the left, all other terms to the right
x=-3
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