7(4x-4)-6=2(3x-1)

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Solution for 7(4x-4)-6=2(3x-1) equation: 



7(4x-4)-6=2(3x-1)

We move all terms to the left:

7(4x-4)-6-(2(3x-1))=0

We multiply parentheses

28x-(2(3x-1))-28-6=0



We calculate terms in parentheses: -(2(3x-1)), so:

2(3x-1)

We multiply parentheses

6x-2

Back to the equation:

-(6x-2)



We add all the numbers together, and all the variables

28x-(6x-2)-34=0

We get rid of parentheses

28x-6x+2-34=0

We add all the numbers together, and all the variables

22x-32=0

We move all terms containing x to the left, all other terms to the right

22x=32

x=32/22

x=1+5/11

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