7(4x-4)=(-7x+7)+112

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Solution for 7(4x-4)=(-7x+7)+112 equation: 



7(4x-4)=(-7x+7)+112

We move all terms to the left:

7(4x-4)-((-7x+7)+112)=0

We multiply parentheses

28x-((-7x+7)+112)-28=0



We calculate terms in parentheses: -((-7x+7)+112), so:

(-7x+7)+112

We get rid of parentheses

-7x+7+112

We add all the numbers together, and all the variables

-7x+119

Back to the equation:

-(-7x+119)



We get rid of parentheses

28x+7x-119-28=0

We add all the numbers together, and all the variables

35x-147=0

We move all terms containing x to the left, all other terms to the right

35x=147

x=147/35

x=4+1/5

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