7(4x-4)=4(-7x+7)+112

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Solution for 7(4x-4)=4(-7x+7)+112 equation: 



7(4x-4)=4(-7x+7)+112

We move all terms to the left:

7(4x-4)-(4(-7x+7)+112)=0

We multiply parentheses

28x-(4(-7x+7)+112)-28=0



We calculate terms in parentheses: -(4(-7x+7)+112), so:

4(-7x+7)+112

We multiply parentheses

-28x+28+112

We add all the numbers together, and all the variables

-28x+140

Back to the equation:

-(-28x+140)



We get rid of parentheses

28x+28x-140-28=0

We add all the numbers together, and all the variables

56x-168=0

We move all terms containing x to the left, all other terms to the right

56x=168

x=168/56

x=3

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