7(4x-5)+12x=13+4(11-13x)

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Solution for 7(4x-5)+12x=13+4(11-13x) equation: 



7(4x-5)+12x=13+4(11-13x)

We move all terms to the left:

7(4x-5)+12x-(13+4(11-13x))=0

We add all the numbers together, and all the variables

7(4x-5)+12x-(13+4(-13x+11))=0

We add all the numbers together, and all the variables

12x+7(4x-5)-(13+4(-13x+11))=0

We multiply parentheses

12x+28x-(13+4(-13x+11))-35=0



We calculate terms in parentheses: -(13+4(-13x+11)), so:

13+4(-13x+11)

determiningTheFunctionDomain
4(-13x+11)+13

We multiply parentheses

-52x+44+13

We add all the numbers together, and all the variables

-52x+57

Back to the equation:

-(-52x+57)



We add all the numbers together, and all the variables

40x-(-52x+57)-35=0

We get rid of parentheses

40x+52x-57-35=0

We add all the numbers together, and all the variables

92x-92=0

We move all terms containing x to the left, all other terms to the right

92x=92

x=92/92

x=1

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