7(4x-5)=28x-35

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Solution for 7(4x-5)=28x-35 equation:


Simplifying
7(4x + -5) = 28x + -35

Reorder the terms:
7(-5 + 4x) = 28x + -35
(-5 * 7 + 4x * 7) = 28x + -35
(-35 + 28x) = 28x + -35

Reorder the terms:
-35 + 28x = -35 + 28x

Add '35' to each side of the equation.
-35 + 35 + 28x = -35 + 35 + 28x

Combine like terms: -35 + 35 = 0
0 + 28x = -35 + 35 + 28x
28x = -35 + 35 + 28x

Combine like terms: -35 + 35 = 0
28x = 0 + 28x
28x = 28x

Add '-28x' to each side of the equation.
28x + -28x = 28x + -28x

Combine like terms: 28x + -28x = 0
0 = 28x + -28x

Combine like terms: 28x + -28x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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