7(4x-5)=4(20x+1)

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Solution for 7(4x-5)=4(20x+1) equation: 



7(4x-5)=4(20x+1)

We move all terms to the left:

7(4x-5)-(4(20x+1))=0

We multiply parentheses

28x-(4(20x+1))-35=0



We calculate terms in parentheses: -(4(20x+1)), so:

4(20x+1)

We multiply parentheses

80x+4

Back to the equation:

-(80x+4)



We get rid of parentheses

28x-80x-4-35=0

We add all the numbers together, and all the variables

-52x-39=0

We move all terms containing x to the left, all other terms to the right

-52x=39

x=39/-52

x=-3/4

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