7(4x-5)=42x+1

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Solution for 7(4x-5)=42x+1 equation: 



7(4x-5)=42x+1

We move all terms to the left:

7(4x-5)-(42x+1)=0

We multiply parentheses

28x-(42x+1)-35=0

We get rid of parentheses

28x-42x-1-35=0

We add all the numbers together, and all the variables

-14x-36=0

We move all terms containing x to the left, all other terms to the right

-14x=36

x=36/-14

x=-2+4/7

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