7(4x-5)=9(3x-1)+6

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Solution for 7(4x-5)=9(3x-1)+6 equation: 



7(4x-5)=9(3x-1)+6

We move all terms to the left:

7(4x-5)-(9(3x-1)+6)=0

We multiply parentheses

28x-(9(3x-1)+6)-35=0



We calculate terms in parentheses: -(9(3x-1)+6), so:

9(3x-1)+6

We multiply parentheses

27x-9+6

We add all the numbers together, and all the variables

27x-3

Back to the equation:

-(27x-3)



We get rid of parentheses

28x-27x+3-35=0

We add all the numbers together, and all the variables

x-32=0

We move all terms containing x to the left, all other terms to the right

x=32

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