7(4x-7)=7x+35

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Solution for 7(4x-7)=7x+35 equation: 



7(4x-7)=7x+35

We move all terms to the left:

7(4x-7)-(7x+35)=0

We multiply parentheses

28x-(7x+35)-49=0

We get rid of parentheses

28x-7x-35-49=0

We add all the numbers together, and all the variables

21x-84=0

We move all terms containing x to the left, all other terms to the right

21x=84

x=84/21

x=4

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