7(4x-8)(2x-9)=0

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Solution for 7(4x-8)(2x-9)=0 equation:



7(4x-8)(2x-9)=0
We multiply parentheses ..
7(+8x^2-36x-16x+72)=0
We multiply parentheses
56x^2-252x-112x+504=0
We add all the numbers together, and all the variables
56x^2-364x+504=0
a = 56; b = -364; c = +504;
Δ = b2-4ac
Δ = -3642-4·56·504
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-364)-140}{2*56}=\frac{224}{112} =2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-364)+140}{2*56}=\frac{504}{112} =4+1/2 $

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