7(4x-9)(6x)=-26

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Solution for 7(4x-9)(6x)=-26 equation:



7(4x-9)(6x)=-26
We move all terms to the left:
7(4x-9)(6x)-(-26)=0
We add all the numbers together, and all the variables
7(4x-9)6x+26=0
We multiply parentheses
168x^2-378x+26=0
a = 168; b = -378; c = +26;
Δ = b2-4ac
Δ = -3782-4·168·26
Δ = 125412
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{125412}=\sqrt{4*31353}=\sqrt{4}*\sqrt{31353}=2\sqrt{31353}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-378)-2\sqrt{31353}}{2*168}=\frac{378-2\sqrt{31353}}{336} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-378)+2\sqrt{31353}}{2*168}=\frac{378+2\sqrt{31353}}{336} $

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