7(4y-36)=35y

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Solution for 7(4y-36)=35y equation: 



7(4y-36)=35y

We move all terms to the left:

7(4y-36)-(35y)=0

We add all the numbers together, and all the variables

-35y+7(4y-36)=0

We multiply parentheses

-35y+28y-252=0

We add all the numbers together, and all the variables

-7y-252=0

We move all terms containing y to the left, all other terms to the right

-7y=252

y=252/-7

y=-36

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