7(4y-5)=11(2y-1)

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Solution for 7(4y-5)=11(2y-1) equation:


Simplifying
7(4y + -5) = 11(2y + -1)

Reorder the terms:
7(-5 + 4y) = 11(2y + -1)
(-5 * 7 + 4y * 7) = 11(2y + -1)
(-35 + 28y) = 11(2y + -1)

Reorder the terms:
-35 + 28y = 11(-1 + 2y)
-35 + 28y = (-1 * 11 + 2y * 11)
-35 + 28y = (-11 + 22y)

Solving
-35 + 28y = -11 + 22y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-22y' to each side of the equation.
-35 + 28y + -22y = -11 + 22y + -22y

Combine like terms: 28y + -22y = 6y
-35 + 6y = -11 + 22y + -22y

Combine like terms: 22y + -22y = 0
-35 + 6y = -11 + 0
-35 + 6y = -11

Add '35' to each side of the equation.
-35 + 35 + 6y = -11 + 35

Combine like terms: -35 + 35 = 0
0 + 6y = -11 + 35
6y = -11 + 35

Combine like terms: -11 + 35 = 24
6y = 24

Divide each side by '6'.
y = 4

Simplifying
y = 4

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